Question

4x^2- 25-(2x-5)(2x-7)=0

Answer 1

  4x^2-25-(2x-5)(2x+7)=0 
<=> 4x^2 - 25 - (4x^2 + 14x - 10x - 35) = 0 
<=> 4x^2 - 25 - 4x^2 - 14x + 10x + 35 = 0 
<=> -4x + 10 = 0 
<=> x = -10/-4 
<=> x = 5/2

Answer 2

  4x^2-25-(2x-5)(2x+7)=0 
<=> 4x^2 - 25 - (4x^2 + 14x - 10x - 35) = 0 
<=> 4x^2 - 25 - 4x^2 - 14x + 10x + 35 = 0 
<=> -4x + 10 = 0 
<=> x = -10/-4 
<=> x = 5/2