Question

\(4^{x+1}\cdot2=32\)\(\left(x-\frac{2}{3}\right)^{2=}\frac{25}{81}\)\(2^{x+3}+2^x=288\)so sánh\(500^{300}vs300^{500}\)\(4^{45}vs3^{60}\)

Answer 1

\(4^{x+1}.2=32\)

\(4^{x+1}=32:2\)

\(4^{x+1}=16\)

\(4^{x+1}=4^2\)

\(\Rightarrow x+1=2\)

\(\Rightarrow x=1\)

vậy \(x=1\)

\(\left(x-\frac{2}{3}\right)^2=\frac{25}{81}\)

\(\left(x-\frac{2}{3}\right)^2=\left(\frac{5}{9}\right)^2\)

\(\Rightarrow x-\frac{2}{3}=\frac{5}{9}\)

\(\Rightarrow x=\frac{11}{9}\)

vậy \(x=\frac{11}{9}\)

\(500^{300}=\left(500^3\right)^{100}=125000000^{100}\)

\(300^{500}=\left(300^5\right)^{100}\)

vì \(\left(500^3\right)^{100}< \left(300^3\right)^{100}\)nên\(500^{300}< 300^{500}\)

\(4^{45}=\left(4^9\right)^5=262144^5\)

\(3^{60}=\left(3^{12}\right)^5=531441^5\)

vì  \(262144^5< 531441^5\) nên \(4^{45}< 3^{60}\)