\(\Leftrightarrow\left|4x-7\right|\left(\left|4x-7\right|-5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}\left|4x-7\right|=0\\\left|4x-7\right|=5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x-7=0\\4x-7=5\\7-4x=5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{4}\\x=3\\x=\dfrac{1}{2}\end{matrix}\right.\)
|2 + 3x| = |4x - 3|
|3/2x + 1/2| = |4x - 1|
|5/4x - 7/2| - |5/8x + 3/5| = 0
|7/5x + 3/2| - |4/3 - 1/4| = 0
a, (4x^2 - 2)^2 = 196/81
b, (2x-4)^2016 + | x^2-4 | = 0
c, (7 - 3x)^2020 = (3x - 7)^2018
d, (4x - 7)^2 -5|7 - 4x| = 0
Giúp mik vs!
Tìm x:
1) \(\left(4x-7\right)^2-5\times\left|7-4x\right|=0\)
7.1 cho f (x) = X^5 + 3x^2-5x^3-x^7+x^3+2x^2+X^5-4x^2+2x^7
cho g(x)=x^4+4x^3-5x^8-x^7+x^3+x^2-2x^7+x^4- 4x^2-x^8
1, 3/x-7/-12/4x+8/=3x-8
2, -5/x-7/+3/3-x/=12x-8
3, /x-7/ -/3x-5/=0
(-5/4x+2,15)[2 3/7 -(-1/2x)]=0
2 3/7 là hai trên ba phần bảy nhé ae
