\(4\left(x-2\right)+x^2-5x=0\)
\(=>4\left(x-2\right)+x\left(x-5\right)\)
\(=>\left(x-5\right)\left(4+x\right)=0\)
\(=>\orbr{\begin{cases}x-5=0\\4+x=0\end{cases}=>\orbr{\begin{cases}x=5\\x=-4\end{cases}}}\)
\(4\left(x-5\right)+x^2-5x=0\)
\(\Leftrightarrow4\left(x-5\right)+x\left(x-5\right)=0\)
\(\Leftrightarrow\left(x-5\right)\left(4+x\right)=0\)
\(\Leftrightarrow\hept{\begin{cases}x-5=0\\4+x=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=5\\x=-4\end{cases}}\)
(Nhớ click cho mình với nha!)
4(x-5)+x2-5x=0
4x-20+x2-5x=0
4(x-5)+x(x-5)=0
(x-5)(4+x)=0
\(\Rightarrow\hept{\begin{cases}x-5=0\\4+x=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=5\\x=-4\end{cases}}}\)
