(4x+5):3-121:11=4
(4x+5):3-11=4
(4x+5):3=15
4x+5=45
4x=40
x=10.
1+3+5+...+x=1600
Gọi x=2k+1
Ta có 1+3+...+x=1600
1+3+..+2k+1=1600
(2k+2)[(2k+1-1)/2+1]/2=1600
(2k+2)(k+1)=3200
2(k+1)(k+1)=3200
(k+1)^2=1600
=>k+1=40
k=39. Vậy x=2k+1=2.39+1=79.
2^x+2^x+3=144
2^x(1+2^3)=144
2^x.9=144
2^x=16
2^x=2^4
=>x=4
(x-5)^4=(x-5)^6
(x-5)^6-(x-5)^4=0
(x-5)^4[(x-5)^2-1]=0
(x-5)^4=0, (x-5)^2-1=0
x-5=0, (x-5)^2=1
x=5, x-5=1, x-5=-1
x=5, x=6, x=4.