Question

4x - 3z = 6y - x = z

và 2x + 3y + 4z = 19     

Tìm x,y,z :    Giúp mk nha , Thanks

Answer 1

\(\hept{\begin{cases}4x-3z=z\\6y-x=z\\2x+3y+4z=19\end{cases}}\)

\(\Leftrightarrow\)\(\hept{\begin{cases}x=z\\6y-x=z\\2x+3y+4z=19\end{cases}}\)

\(\Leftrightarrow\)\(\hept{\begin{cases}x=z\\3y=z=x\\2x+3y+4z=19\end{cases}}\)

\(\Leftrightarrow\)2x+x+4x=19 \(\Leftrightarrow\)x=z = \(\frac{19}{7}\)

y=\(\frac{19}{21}\)

Answer 2

x= \(\frac{19}{7}\)

y= \(\frac{19}{21}\)

z= \(\frac{19}{7}\)

Answer 3

bn làm rõ dc ko