\(\Rightarrow3x=12\Rightarrow x=4\)
Tuyển Cộng tác viên Hoc24 nhiệm kì 30 tại đây: https://forms.gle/T8wg79khMGHeXQuDA
\(\Rightarrow3x=12\Rightarrow x=4\)
12-4x+(3-x).x=0
{x + 2 } - 2=0 {x + 3}+1 =7
{x + 3 } + 4 = 12 {5x + 4} - 1= 13
{ 4x - 8 } + 3 =12 3 + {x - 5 } = 14
Tìm x:
-5(3x-7) - ( -15x+3) - ( 12 -x ) =-4
-3(4x-2) - ( -12+8) - (-x)=0
(4x-12)(x³+64)=0
1) (3x-6)(x+5)+4(x-2)=0
2) 3(x-5)(2x+9)+3x-15=0
3) (x2-16)(12-4x)=0
4) (9-x2)(4x-8)=0
5) (8-x3)(5x-125)=0
6) 4x=8
I x - 12 I = 12-x
l x -12l + x-12=0
4x+5-lx-4l=11 ( x > -3 )
l-x+l31-(-89)l l = 14
tìn x ,biết
(x^2-36)(x^2-3)<0
2.(3x+12)>=0
(x^2+1)(4x-24)<=0
x^2+5x=0
tìm x ,biết
(x^2-36)(x^2-3)<0
2.(3x+12)>=0
(x^2+1)(4x-24)<=0
x^2+5x=0
122.(12-4x)=0
(3x -111):20=0
3x+2x=1505
2018x- x=2017