\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)
\(=\left(49-14\right)+\left(\frac{8}{23}-\frac{8}{23}\right)+5\frac{7}{32}\)
\(=35+5\frac{7}{32}\)
\(=34\frac{32}{32}+5\frac{7}{32}\)
\(=\left(34+5\right)+\left(\frac{32}{32}+\frac{7}{32}\right)\)
\(=39+\frac{39}{32}\)
\(=39\frac{39}{32}=40\frac{7}{32}\)
tính:
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
tính hợp lí giá trị biểu thức sau :
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
Tính hợp lý giá trị biểu thức sau
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
Tính hợp lí\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
Giải chi tiết nhé
\(a,49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(b,71\frac{38}{45}-\left(43\frac{8}{45}-1\frac{17}{57}\right)\)
\(d,\left(19\frac{15}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)
Bài 1 TÍNH
\(\frac{5}{16}:0,125-\left(2\frac{1}{4}-0,6\right).\frac{10}{11}\)
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(A=49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(B=6\frac{3}{8}+5\frac{1}{2}\)
\(C=\frac{-3}{7}.\frac{5}{9}+\frac{4}{9}.\frac{-3}{7}+2\frac{3}{7}\)
\(D=8\frac{2}{7}-\left(3\frac{4}{9}+4\frac{2}{7}\right)\)
Tính hợp lý giá trị của biểu thức sau:
\(A=49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(B=71\frac{38}{45}-\left(43\frac{8}{45}-1\frac{17}{57}\right)\)
\(C=\frac{-3}{7}.\frac{5}{9}+\frac{4}{9}.\frac{-3}{7}+2\frac{3}{7}\)
\(D=\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)
Tính hợp lí (nếu có thể)
a/A=\(49\frac{8}{23}\)- (\(5\frac{7}{32}\)+ \(14\frac{8}{23}\))
b/B=\(\frac{4}{9}\)\(\div\frac{1}{6}+\frac{4}{9}\div\frac{1}{12}-\frac{4}{9}\div\frac{1}{8}\)
