\(\frac{4}{9}\).\(\frac{13}{3}\)-\(\frac{4}{3}\).\(\frac{40}{9}\)=\(\frac{4.13}{9.3}\)-\(\frac{4.40}{3.9}\)
=\(\frac{\left(4.13\right)-\left(4.40\right)}{9.3}\)
= \(\frac{4\left(13-40\right)}{27}\)
=\(\frac{4\left(-27\right)}{27}\)
=-4
\(\frac{4}{9}\cdot\frac{13}{3}-\frac{4}{3}\cdot\frac{40}{9}\)
\(=\frac{4}{3}\cdot\frac{13}{9}-\frac{4}{3}\cdot\frac{40}{9}\)
\(=\frac{4}{3}\cdot\left(\frac{13}{9}-\frac{40}{9}\right)\)
\(=\frac{4}{3}\cdot-3=-4\)
=4/3 x 1/3 x 13/3 - 4/3 x 40/9
=4/3 x (1/3 x 13/3 - 40/9)
=4/3 x (-3)
=-4
Ta có : \(\frac{4}{9}.\frac{13}{3}-\frac{4}{3}.\frac{40}{9}\)
\(=\frac{4}{9}.\frac{13}{3}-\frac{40}{3}.\frac{4}{9}\)
\(=\frac{4}{9}.\left(\frac{13}{3}-\frac{40}{3}\right)\)
\(=\frac{4}{9}.\left(-9\right)\)
\(=\frac{4}{9}.\frac{-9}{1}\)
\(=-4\)
\(\frac{4}{9}\)x\(\frac{13}{3}\)-\(\frac{4}{3}\)x\(\frac{40}{9}\)
= \(\frac{52}{27}\) - \(\frac{160}{27}\)
= - 4
Theo mình thì nên tính nhanh.