\(\frac{4}{5}.x-x-\frac{3}{2}.x+\frac{5}{6}=\frac{1}{2}-\frac{4}{3}\)đề nảy hả
\(\frac{4}{5}x-x-\frac{3}{2}x+\frac{5}{6}=\frac{1}{2}-\frac{4}{3}\)
\(-\frac{1}{5}x-\frac{3}{2}x=-\frac{5}{6}-\frac{5}{6}\)
\(-\frac{17}{10}x=-\frac{10}{6}\)
\(x=\frac{50}{51}\)
Bài làm:
Ta có: \(\frac{4}{5}x-x-\frac{3}{2}x+\frac{5}{6}=\frac{1}{2}-\frac{4}{3}\)
\(\Leftrightarrow-\frac{17}{10}x=-\frac{5}{3}\)
\(\Rightarrow x=\frac{50}{51}\)
Bài làm :
Ta có:
\(\frac{4}{5}x-x-\frac{3}{2}x+\frac{5}{6}=\frac{1}{2}-\frac{4}{3}\)
\(\Leftrightarrow-\frac{17}{10}x=-\frac{5}{3}\)
\(\Leftrightarrow x=\frac{50}{51}\)
Vậy x=50/51