Question

4.2^x+3.2^x+1=80

Answer 1

4.2\(^x\)+3.2\(^{x+1}\)=80

4.2\(^x\)+3.2\(^x\).2\(^1\)=80

2\(^x\).(4+3.2)=80

2\(^x\).10=80

2\(^x\)=8

⇒x=3 vì 2\(^3\)=8

Answer 2

= 2² .2^X+3.2X.2¹=80

=4.2^X+3.2.2^X

= 4.2^X+6.2x

=2X.(4+6)

= 2X.10=80

2X=80:10

2X= 8

X= 8:2

X=4

 

Answer 3

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