Question

4-x=2(x-4)^2

Answer 1

\(4-x=2\left(x-4\right)^2\)

\(\Leftrightarrow2\left(x-4\right)^2+\left(x-4\right)=0\)

\(\Leftrightarrow\left(x-4\right)\left(2x-7\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=\dfrac{7}{2}\end{matrix}\right.\)

Answer 2

\(4-x=2\left(x-4\right)^2\)

\(4-x=2\left(x^2-8x+16\right)\)

\(4-x=2x^2-16x+32\)

\(x=4-2x^2-16x+32\)