Question

4. Tìm x biết

a, x - \(\frac{1}{3}\)= \(\frac{3}{4}\)                            c, x : \(\frac{1}{4}\)=  18 \(\frac{1}{2}\)

b, x + 2 \(\frac{1}{2}\)= 3\(\frac{3}{4}\)                     d, \(\frac{2}{9}\):  x = \(\frac{2}{3}\)

Answer 1

a, \(x-\frac{1}{3}=\frac{3}{4}\)

\(x=\frac{3}{4}+\frac{1}{3}\)

\(x=\frac{9}{13}+\frac{4}{12}=\frac{13}{12}\)

Answer 2

a. \(x=\frac{3}{4}+\frac{1}{3}\)

\(x=\frac{10}{12}\)

b. \(x+\frac{5}{2}=\frac{15}{4}\)

\(x=\frac{15}{4}-\frac{5}{2}\)

\(x=\frac{5}{4}\)

c. \(x:\frac{1}{4}=\frac{37}{2}\)

\(x=\frac{37}{2}\)x \(\frac{1}{4}\)

\(x=\frac{37}{8}\)

d. \(x=\frac{2}{9}:\frac{2}{3}\)

\(x=\frac{2}{9}\)x \(\frac{3}{2}\)

\(x=\frac{1}{3}\)

Answer 3

d,\(\frac{2}{9}:x=\frac{3}{3}\)

\(x=\frac{2}{9}:\frac{2}{3}\)

\(x=\frac{2}{9}.\frac{3}{2}\)

\(x=\frac{1}{3}.\frac{1}{1}\)

\(x=\frac{1}{3}\)

Answer 4

a) \(x-\frac{1}{3}=\frac{3}{4}\)

=> \(x=\frac{3}{4}+\frac{1}{3}\)

=> \(x=\frac{13}{12}\)

b) \(x+2\frac{1}{2}=3\frac{3}{4}\)

=> \(x+\frac{5}{2}=\frac{15}{4}\)

=> \(x=\frac{15}{4}-\frac{5}{2}\)

=> \(x=\frac{5}{4}\)

c)\(x:\frac{1}{4}=18\frac{1}{2}\)

\(x:\frac{1}{4}=\frac{37}{2}\)

=> \(x=\frac{37}{2}:\frac{1}{4}\)

=> \(x=74\)

d) \(\frac{2}{9}:x=\frac{2}{3}\)

=> \(x=\frac{2}{9}:\frac{2}{3}\)

=> \(x=\frac{1}{3}\)