a, \(x-\frac{1}{3}=\frac{3}{4}\)
\(x=\frac{3}{4}+\frac{1}{3}\)
\(x=\frac{9}{13}+\frac{4}{12}=\frac{13}{12}\)
a. \(x=\frac{3}{4}+\frac{1}{3}\)
\(x=\frac{10}{12}\)
b. \(x+\frac{5}{2}=\frac{15}{4}\)
\(x=\frac{15}{4}-\frac{5}{2}\)
\(x=\frac{5}{4}\)
c. \(x:\frac{1}{4}=\frac{37}{2}\)
\(x=\frac{37}{2}\)x \(\frac{1}{4}\)
\(x=\frac{37}{8}\)
d. \(x=\frac{2}{9}:\frac{2}{3}\)
\(x=\frac{2}{9}\)x \(\frac{3}{2}\)
\(x=\frac{1}{3}\)
d,\(\frac{2}{9}:x=\frac{3}{3}\)
\(x=\frac{2}{9}:\frac{2}{3}\)
\(x=\frac{2}{9}.\frac{3}{2}\)
\(x=\frac{1}{3}.\frac{1}{1}\)
\(x=\frac{1}{3}\)
a) \(x-\frac{1}{3}=\frac{3}{4}\)
=> \(x=\frac{3}{4}+\frac{1}{3}\)
=> \(x=\frac{13}{12}\)
b) \(x+2\frac{1}{2}=3\frac{3}{4}\)
=> \(x+\frac{5}{2}=\frac{15}{4}\)
=> \(x=\frac{15}{4}-\frac{5}{2}\)
=> \(x=\frac{5}{4}\)
c)\(x:\frac{1}{4}=18\frac{1}{2}\)
\(x:\frac{1}{4}=\frac{37}{2}\)
=> \(x=\frac{37}{2}:\frac{1}{4}\)
=> \(x=74\)
d) \(\frac{2}{9}:x=\frac{2}{3}\)
=> \(x=\frac{2}{9}:\frac{2}{3}\)
=> \(x=\frac{1}{3}\)