\(4^{40}=\left(2^2\right)^{40}=2^{80}\)
\(4^{40}=2^n\)
\(\Rightarrow\left(2^2\right)^{40}=2^n\)
\(\Rightarrow2^{80}=2^n\)
\(\Rightarrow n=80\)
440 = (22)40 = 440
SUY RA 440 = 440
K MK NHÉ
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\(4^{40}\)
\(=\left(2^2\right)^{40}\)
\(=2^{80}\)
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