Question

3x(x-2)-(x+2)(3x+1)=0

Answer 1

\(3x\left(x-2\right)-\left(x+2\right)\left(3x+1\right)=0\)

\(3x^2-6x-\left(3x^2+x+6x+2\right)=0\)

\(3x^2-6x-3x^2-x-6x-2=0\)

\(3x^2-3x^2-6x-6x-x-2=0\)

\(-13x-2=0\)

\(-13x=2\)

\(x=-\dfrac{2}{13}\)

 

Answer 2

3x(x - 2) - (x + 2)(3x + 1) = 0

3x² - 6x - 3x² - x - 6x - 2 = 0

-13x - 2 = 0

-13x = 2

x = -2/13

Answer 3

<=> 3x^2 - 6x - 3x^2 - x -6x - 2 = 0

<=> -13x = 2 => x =- 2/13 

Answer 4