Question

3x(x-2) + 4x - 8 = 0

Answer 1

\(=3x\left(x-2\right)+4\left(x-2\right)=0\\ =\left(3x+4\right)\left(x-2\right)=0\\ =>3x+4=0\\ =>x-2=0\\=>3x=-4\\ =>x=2\\ =>x=\dfrac{4}{3}\)

Answer 2

\(\Leftrightarrow3x\left(x-2\right)+4\left(x-2\right)=0\\ \Leftrightarrow\left(x-2\right)\left(3x+4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=-\dfrac{4}{3}\end{matrix}\right.\)