\(\Leftrightarrow3x+5=6-\left(x+1\right)\)
\(\Leftrightarrow3x+5=6-x-1\)
\(\Leftrightarrow3x+x=6-5-1\)
\(\Leftrightarrow4x=0\)
\(\Leftrightarrow x=0:4\)
\(\Leftrightarrow x=0\)
Vậy: S = {0}
\(3x+5=6-x-1 =>3x+5=5-x =>3x+5-5+x=0 =>4x=0 =>x=0\)Chúc em học tốt
\(\Leftrightarrow3x+5-\left(6-x-1\right)=0\)
\(\Leftrightarrow3x+5-6+x+1=0\)
\(\Leftrightarrow4x=0\)
\(\Rightarrow x\in R\)