-3(x+4)(x-7)+7(x-5)(x-1)
=\(-3\left(x^2-3x-28\right)+7\left(x^2-6x+5\right)\)
= \(-3x^2+9x+84+7x^2-42x+35\)
= \(4x^2-33x+119\)
\(-3\left(x+4\right)\left(x+7\right)+7\left(x-5\right)\left(x-1\right)\)
\(=-3x^2+21x-12x+84+7x^2-7x-35x+35=4x^2-33x+119\)
-3( x + 4 )( x - 7 ) + 7( x - 5 )( x - 1 )
= -3( x2 - 3x - 28 ) + 7( x2 - 6x + 5 )
= -3x2 + 9x + 84 + 7x2 - 42x + 35
= 4x2 - 33x + 119
