Question

\(3x^2+4x-4=0\)

Answer 1

3x² + 4x - 4 = 0
<=> 3x² + 6x - 2x - 4 = 0

<=> (3x - 2)(x + 2) = 0

<=> x = 2/3 hoặc x = -2

Vậy S = {2/3 ; -2}

Answer 2

\(3x^2+4x-4=0\)

\(3x^2+6x-2x-4=0\)

\(3x\left(x+2\right)-2\left(x+2\right)=0\)

\(\left(x+2\right)\left(3x-2\right)=0\)

\(=>x+2=0=>x=-2\)

hoặc \(3x-2=0=>x=\dfrac{2}{3}\)