\(3^{x+1}=9^x\)
\(\Rightarrow3^{x+1}=\left(3^2\right)^x\)
\(\Rightarrow3^{x+1}=3^{2x}\)
\(\Rightarrow x+1=2x\)
\(\Rightarrow2x-x=1\)
\(\Rightarrow x=1\)
3x+1=9x
ma :9x=(32)x
=> 3x+1=(32)x
=> 3x+1=32x
=>x+1=2x
2x chia hết cho x+1
ma 2x=(x+1).2-2
=>(x+1).2-2 CHIA HẾT CHO X+1
=>2 chia hết cho n+1
mà 2 chia hết cho 1;2
vậy x=0;1