Question

3.(x+1)-32=67

Answer 1

3.(x+1)-32=67

=> 3(x+1)=67+32

=> 3(x+1)=99

=> x-1=99:3

=> x-1=33

=> x=33+1

=> x=34

Answer 2

3.(x+1)-32=67

3.(x+1)=67+32

3.(x+1)=99

x+1=99:3

x+1=33

    x = 33 - 1

    x= 32

Answer 3

3(x+1)-32=67

<=>3x+3-32=67

<=>3x=67-3+32

<=>3x=96

<=>x=96:32

<=>x=32