3x - (x - 5) = 25
3x - x + 5 = 25
2x + 5 = 25
2x = 25 - 5
2x = 20
x = 20 : 2
x = 10
Vậy x = 10
3x-(x-5)=25
=> 3x-x+5=25
=> 3x-x=25-5
=> 2x=20
=> x=20:2
=>x=10
tick nhé
3x-(x-5) =25
3x-x+5 = 25
2x+5 = 25
2x = 2
x = 20:2
=> x = 10
3x - (x - 5) = 25
3x - x + 5 = 25
2x + 5 = 25
2x = 25 - 5
2x = 20
x = 20 : 2
x = 10
Vậy x = 10
3x-(x-5)=25
=> 3x-x+5=25
=> 3x-x=25-5
=> 2x=20
=> x=20:2
=>x=10
tick nhé
3x-(x-5) =25
3x-x+5 = 25
2x+5 = 25
2x = 2
x = 20:2
=> x = 10
x-2=24
5.(5-x)=-25
3x-7=22.5
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
tìm x biết 3x-(x-5)=25
Tìm X :
-15 5 . (3X - 1)=25
3x-(x-5)bằng 25
Câu 1:
(phần a lm r)
b) 120:{54-[50:2-(3\(^2\)-2.4)]}
Câu 2:
a) x-25=39 b) 3x - 6= 3\(^5\):3\(^2\)
a) x-25=39
b) 3x - 6 = 3
a, 2.x + 7 = 15
b, 25 – 3.(6 – x) = 22
c, [(2x – 11) : 3 + 1].5 = 20
d, (25 – 2x)3 : 5 – 32 = 42
e, 2 . 3x = 10 . 312 + 8 . 274
g, x – 12 = (–8) + (–17)
h, 7 – 2x = 18 – 3x
i, 3(x + 5) – x – 11 = 24
A) x+20=12 ; B)25-x=-5 ; C) 22-(3x+4)=30
Tìm x :
25-(3x + 5) = 8