3\(^x\) = \(\dfrac{9^4}{81^3}\)
3\(^x\) = \(\dfrac{\left(3^2\right)^4}{\left(3^4\right)^3}\)
3\(^x\) = \(\dfrac{3^8}{3^{12}}\)
3\(^x\) = 3-4
\(x\) = -4
Vậy \(x\) = -4
3x+1 + 3x+2 = (96 : 94) . 4
Trả lời gấp ạ
3x : 9 = 391
81 : 3x + 1 = 9
(-3)3x+1=1/81
(-3/4)^3x+5=(81/256)^-1
1, Tìm x
a,3x.(2x+3)-(2x+5).(3x-2)=8
b,5x(x+2)-x.(2x-7)-3x^2=81
(1/3)^2x-1 - (1/3)^2 = -2/27
3^7-3x = 81
Tìm x
(-3/4)3x-1=256/81
3x = 4y = 5z và x + y + z = -94
\(\frac{x-1}{2}\) =\(\frac{y+3}{4}\) =\(\frac{z-5}{6}\) và 5z - 3x -4y =50
(\(\dfrac{-3}{4}\))3x - 1 = \(\dfrac{256}{81}\)
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