Question

3x = 8y và x - y =-10

Answer 1

Áp dụng t.c dtsbn:

\(3x=8y\Rightarrow\dfrac{x}{8}=\dfrac{y}{3}=\dfrac{x-y}{8-3}=\dfrac{-10}{5}=-2\\ \Rightarrow\left[{}\begin{matrix}x=-16\\y=-6\end{matrix}\right.\)

Answer 2

\(3x=8y\Rightarrow\dfrac{x}{8}=\dfrac{y}{3}\)

Áp dụng TCDTSBN ta có:

\(\dfrac{x}{8}=\dfrac{y}{3}=\dfrac{x-y}{8-3}=\dfrac{-10}{5}=-2\)

\(\dfrac{x}{8}=-2\Rightarrow x=-16\\ \dfrac{y}{3}=-2\Rightarrow y=-6\)