Question

(3^x -81)(x² +1)= 0

Answer 1

`#3107.101107`

\(\left(3^x-81\right)\left(x^2+1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}3^x-81=0\\x^2+1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}3^x=81\\x^2=-1\left(\text{vô lý}\right)\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}3^x=3^3\\x\in\varnothing\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x\in\varnothing\end{matrix}\right.\)

Vậy, `x = 3.`