Question

(3x-7)^2012=(3x-7)^2014

        Giúp mìh với!!!

 

Answer 1

( 3x - 7 ) ^ 2012 = ( 3x - 7 ) ^ 20147 = 0

( 3x - 7 ) ^ 2014 - ( 3x - 7 ) ^ 2012 = 0

( 3 x - 7 ) ^ 2012 . [ ( 3x - 7 ) ^ 2 - 1 ) = 0

=> ( 3x - 7 ) ^ 2012 = 0 hoặc ( 3x - 7 ) ^ 2 - 1 = 0

          3 x - 7           = 0            ( 3x - 7 ) ^  2   = 1

          3x                 = 7             => 3x - 7 = 1 hoặc 3x - 7 = -1

            x                 = 7 / 3                   x  = 8 / 3           x  = 2

Vậy x = 7 / 3 hoặc x = 8 / 3 hoặc x = 2

Answer 2

(3x-7)^2012=(3x-7)^2014

<=> (3x-7)^2014 - (3x-7)^2012 = 0

<=> (3x-7)^2012.(3x-7)^2 - (3x-7)^2012 = 0

<=> (3x-7)^2012.[(3x-7)^2 - 1] = 0

=> (3x-7)^2012=0 hoặc (3x-7)^2-1=0

<=> 3x-7=0 hoặc (3x-7)^2=1

<=>x=7/3 hoặc 3x-7=-1;1

<=>x=7/3 hoặc x=2;8/3

Vậy .............