Vì \(\left(3x-6\right)^{20}=\left(3x-6\right)^{10}\) nên \(3x-6=-1\) hoặc \(3x-6=0\) hoặc \(3x-6=1\)
(+) \(3x-6=-1=>x=\frac{5}{3}\)
(+)\(3x-6=0=>x=2\)
(+) \(3x-6=1=>x=\frac{7}{3}\)
a) -12+x=5x-20
b) 4x-10=15-x
c) 7x-4=20+3x
d) 3x-6=5x+2
e) 5x-7=-21-2x
f) 15-x=4x-5
g) x+15=20-4x
Tìm x
1) 5x - 16 = 40 + x
2) 4x - 10 = 15 - x
3) 3x - 6 = 5x + 2
4) 15 - x = 4x - 5
5) x - 15 = 6 + 4x
6) -12 + x = 5x - 20
7) 7x - 4 = 20 + 3x
8) 5x - 7 = -21 - 2x
9) x + 15 = 20 - 4x
10) 17 - x = 7 - 6x
1). 20-[4* +(x-6)]=90
2). (х +3).(2х -4)=0
3). 1000:[30+(2" -6)]=3 +4
4). 3x+10 = 4?
5). 164– 2?(x-5)= 5.16
6). 4.2* -3 125
giúp mình giải bài toán.......
1)3x-6=5x+2
2)15-x=4x-5
3)x-15=6+4x
4)-12+x=5x-20
5)7x-4=20+3x
6)5x-7=-21-2x
7)x+15=20-4x
8)17-x=7-6x
9)-4|x-2|=-8
10)-7|x+4|=2.(-7)
tìm số nguyên x biet
-2.(x+6)+6.(x-10)=8
x+5=20-(12-7)
(3x-9).(2x+6)=0
(2x+1).(3-x)=0
a) 3x + 3x+1 + 3x+2 =117
b) 3 + 4 (x - 10) = 32 + 6
tim x, biet:
a,(3x-15)^7=0
b,4^2x-6=1
c,(3-x)^20:(3-x)^10=1(x khac 3)
d,(x-6)^3=(x-6)^2
tìm x thuộc Z
-2(-34-7x)+5c(-3x-14)=2
-13(-7+3x)-(-985+91)=20(-34-x)-6(3x-16)
