\(\frac{3}{x-5}=-\frac{4}{x+2}\)
\(\Rightarrow3x+6=-4x+20\)
\(\Rightarrow7x=14\)
\(\Rightarrow x=2\)
\(\frac{3}{x-5}=\frac{-4}{x+2}\)
\(\Rightarrow3\left(x+2\right)=-4\left(x-5\right)\)
\(\Leftrightarrow3x+6=-4x+20\)
\(\Leftrightarrow7x=14\)
\(\Leftrightarrow x=2\)
\(\frac{3}{x-5}=\frac{-4}{x+2}\)
<=> \(3\left(x+2\right)=\left(x-5\right)\cdot\left(-4\right)\)
<=> \(3x+6=-4x+20\)
<=> \(3x+4x=20-6\)
<=> \(7x=14\)
<=> \(x=2\)
3/x-5= - 4/x+2
=>3.(x+2)=-( - 4).(x-5)
=>3x+3.2= - 4x-(-20)
=>3x+6= - 4x+20
=>4x+3x=20-6
=>7x=14
=>x=14:7
=>x=2
: )
\(\frac{3}{x-5}=\frac{-4}{x+2}\)
\(\Leftrightarrow3\left(x+2\right)=-4\left(x-5\right)\)
\(\Leftrightarrow3x+6=-4x+20\)
\(\Leftrightarrow7x=14\)
\(\Leftrightarrow x=2\)
Vậy \(x=2\)
Ddaeng
3/ x -5 = -4/x+2
--> 3x + 6 = -4x+ 20
--> 7x = 14
--> x = 2
