12 tháng 11 2021 lúc 8:04
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12 tháng 11 2021 lúc 9:02
B) (3x-2)^2 + 9= 25
h/1/4-(2x+1/2)2=0
i/25.(3x-1/2)2=16
k/3.(3x-1/2)3+1/9=0
m/x+1/3=3/9
1/3. (3x - 2) + 25% = -9/6
Tìm x liên quan đến lũy thừa:
1, \(\left(3x-\dfrac{1}{5}\right)^2=\left(\dfrac{-3}{25}\right)^2\)
2, \(\left(2x-\dfrac{1}{3}\right)^2=\left(\dfrac{-2}{9}\right)^2\)
3, \(\left(\dfrac{1}{3}-x\right)^2=\dfrac{9}{25}\)
4, \(\left(5-x\right)^2=25\)
Tìm x biết: (3x+1)^2=25/9
tìm x
(3x-25)-(x-9)=2-x
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
a) (2x+3/5)2-9/25=0
b)3(3x-1/2)3+1/9=0
Tìm x biết:
a) (2x + 3/5)^2 - 9/25 = 0
b) 3.(3x - 1/2)^3 +1/9 =0