Question

(3.x-2)^2+4^2=5^3+3.2^2

tính giá trị biểu thức:

S=5+5^2+5^3+5^4+...5^99

S=5*5^2*5^3*5^4*...5^99

mik học íu mog các bn giúp mik vs

Answer 1

S=5+5^2+5^3+5^4+...5^99

=> 5S=5^2+5^3+5^4+...5^100

=> 5S-S=4S=(5^2+5^3+5^4+...5^100)-(5+5^2+5^3+5^4+...5^99)

=> 4S = 5¹⁰⁰-5

=> S=(5¹⁰⁰-5)/4

S=5*5^2*5^3*5^4*...5^99

=> S=5^1+2+3+...+99

=> S=5^{((99+1).99):2}

=> S=5⁴⁹⁵⁰

Answer 2

(3x-2)+16=125+12

(3x-2)+16=137

3x-2=121

3x=123

x=41

5s=5^2+5^3+5^4+5^5+......+5^100

5s-s=5^100-5

4s=5^100-5

s=(5^100-5):4

kick nhé