d) (3x – 5)(7 – 5x) – (5x + 2)(2 – 3x) = 4 g) 3(2x - 1)(3x - 1) - (2x - 3)(9x - 1) =0 j) (2x – 1)(3x + 1) – (4 – 3x)(3 – 2x) = 3 k) (2x + 1)(x + 3) – (x – 5)(7 + 2x) = 8 m) 2(3x – 1)(2x + 5) – 6(2x – 1)(x + 2) = - 6
tìm x:
a)3(2x-3)+2(2-x)=-3
b)2x(x2-2)+x2(1-2x)-x2=-12
c)3x(2x+3)-(2x+5)(3x-2)=8
d)4x(x - 1) - 3(x2-5)-x2=(x-3)-(x+4)
e)2(3x-1)(2x+5)-6(2x-1)(x+2)=-6
tìm x,y
a) ( 3x-2)^3 - (3x - 2) ( 9x^2 + 6x +4) = 6( 3x+5)(5 - 3x )
b) ( 2x - 1)( 4x^2 - 4x +1) - (2x+ 1)^3+ 3(2x+5)(2x - 5)= -5
Tìm x biết:
a; 3x.(2x+3)-(2x+5x).(3x-2)=8
b;4.(x-1)-3.(x^2-5)_x^2=(x-3)-(x+4)
c; 2.(3x-1).(2x+5)-6.(2x-1).(x+2)=-6
d; 3.(2x-1).(3x-1)-(2x-3.(9x-1)-3=3
giải bất phương trình sau và biểu diễn tập nghiệm trên trục số
(3x-1)-2(2x+1)>2x-3,
1-2x+3(x+1)<3x+5
3-2x+2(-1-2x)>4x-6
4x+2-(2-4x)<2x+1
3x-(2x+1) > 2-3x
(2x-1)-3(1+5x) > 1-5x
3-4(-x-3) < 3x+4
(-1-3x)+(3x-4) > 4x-1
3(1-x)-4(2x+3) > 3-7x
6(2x-6)-3(-1-3x) > 2x+5
3x-4(-1-x) < 2x+5
3x-4(3x+2) < 5x-5
mai phải nộp mong ae giúp
a,4x-8/2x2+1=0 b,x2-x-6/x-3=0 c,x+5/3x-6-1/2=2x-3/2x-4 d,12/1-9x2=1-3x/1+3x-1+3x/1-3x
Bài 4: Tìm x, biết:
a) 3(2x – 3) + 2(2 – x) = –3 ; b) x(5 – 2x) + 2x(x – 1) = 13 ;
c) 5x(x – 1) – (x + 2)(5x – 7) = 6 ; d) 3x(2x + 3) – (2x + 5)(3x – 2) = 8 ;
e) 2(5x – 8) – 3(4x – 5) = 4(3x – 4) + 11; f) 2x(6x – 2x 2 ) + 3x 2 (x – 4) = 8.
1: 3/x+1 + 2/x+2 = 5x+4/x2+ 3x + 2
2: 2/3x + 1 - 15/6x2-x-1 = 3/2x - 1
3: 9/3x - 1 - 5-x/3x2-4x+1 = 4/x+ 1
4:5/x - 2 + 2/x+4 = 3x/x2 + 2x - 8
5: 4/x+6 + 1/x - 3 = 9/x2 + 3x - 18
6:x/x-3 - 2x2 +9/2x2 - 3x - 9= 1/2x + 3
Tìm x biết
a) 3x(2x+3)-(2x+5)(3x-2)=8
b) (3x-4)(2x+1)-(6x+5)(x-3)=3
c) 2(3x-1)(2x+5)-6(2x-1)(x+2)= - 6
d) 3xy(x+y)-(x+y)(x2+y2+2xy)+y3=27
(1) 1>.-3x.(x2 +7x- 1/3)
2. -5x2y4(3x2y3-2x3y2-xy)
3. \(\dfrac{1}{2}\)x3y .(2x4y3-4xy-6)
4. -2x.(3x+20
5. 3x.(5-2x)
6. 2x.(2x2-4x+5)
7. 4x3y2.(-2x2y+4x4-3y2)
8.\(\dfrac{1}{2}\)x3y.( 2x4y3- 4xy -6)