\(\Rightarrow\left(3x-1\right)^{20}-\left(3x-1\right)^{10}=0\\ \Rightarrow\left(3x-1\right)^{10}\left[\left(3x-1\right)^{10}-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}3x-1=0\\\left(3x-1\right)^{10}=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}3x-1=0\\3x-1=1\\3x-1=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=\dfrac{2}{3}\\x=0\end{matrix}\right.\)
(3x-1)^10=(3x-1)^20
tìm x a)(3x-1)^10 =(3x-1)^20
số giá trị của x thỏa mãn (3x - 1)^10 = (3x - 1)^20
tim x biết (3x -1)^10 = (3x-1)^20
Mong các bạn trả lời giúp mk
tìm x:
a) 2016^x=1
b) x^2=x^5
c) (3x-1)^10=(3x-1)^20
Tìm x,biết: a)(x-2,5)^4=(x-2,5)^2
b)(3x-1)^10=(3x-1)^20
c)x^8/243=27
d)32^x.16^x=1024
1/3x=-1/7y va x-y = -20
x/y=3.5 va x-y =10
x/y=7/13 va xy= 91
Tìm x:
1, |5x+13|=2x-7
2,|2x|+|3x-8|-|4x+1|=5x-2
3, |x+1|+|x-3|+|x-10|=20
Tìm x biết
a,
\(|x-1|+|x-2|+|x-3|=2\)
b,
\(|3x+\frac{1}{2}|+|3x+\frac{1}{6}|+|3x+\frac{1}{12}|+|3x+\frac{1}{20}|+...+|3x+380|=58x\)
