\(\left(3x-1\right)\left(\frac{1}{2}x-\frac{2}{5}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3x-1=0\\\frac{1}{2}x-\frac{2}{5}=0\end{cases}\Leftrightarrow\orbr{\begin{cases}3x=1\\\frac{1}{2}x=\frac{2}{5}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{3}\\x=\frac{4}{5}\end{cases}}}\)
KL:...........
Chúc bạn học tốt
( 3x - 1 ) ( 1/2x - 2/5 ) = 0
\(\Rightarrow\)\(\hept{\begin{cases}3x-1=0\\\frac{1}{2}x-\frac{2}{5}=0\end{cases}}\)\(\Rightarrow\)\(\hept{\begin{cases}3x=1\\\frac{1}{2}x=\frac{2}{5}\end{cases}}\)\(\Rightarrow\)\(\hept{\frac{x=\frac{1}{3}}{x=\frac{4}{5}}}\)
( Cái dấu đấy là hoặc nhé )
\(\left(3x-1\right)\left(\frac{1}{2x}-\frac{2}{5}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}3x-1=0\\\frac{1}{2x}-\frac{2}{5}=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{1}{3}\\x=\frac{5}{4}\end{cases}}\)
Vậy x = ......
Có \(\left(3x-1\right)\cdot\left(\frac{1}{2}x-\frac{2}{5}\right)=0\)
\(\Rightarrow\)Có hai trường hợp xảy ra
\(TH1:3x-1=0\)
\(3x=0+1\)
\(3x=1\)
\(x=\frac{1}{3}\)
\(TH2:\frac{1}{2}x-\frac{2}{5}=0\)
\(\frac{1}{2}x=0+\frac{2}{5}\)
\(\frac{1}{2}x=\frac{2}{5}\)
\(x=\frac{2}{5}:\frac{1}{2}\)
\(x=\frac{4}{5}\)
Vậy \(x\in\left\{\frac{1}{3};\frac{4}{5}\right\}\)
