ta co :n+3 chia het cho n+3 =>3(n+3)=3n+9 chia het cho n+3
=> (3n+9) - (3n+2) chi het cho n+3
7 chia het cho n+3
=> n+3 thuoc uoc cua 7={-1; -7 ;1 ;7}
=> n thuoc{-10 ; -4 ;-2 ; 4}
Ta có:3n+2 chia hết cho n+3
=>3n+9-7 chia hết cho n+3
=>3(n+3)-7 chia hết cho n+3
Mà 3(n+3) chia hết cho n+3
=>7 chia hết cho n+3
=>n+3\(\in\)Ư(7)={-7,-1,1,7}
=>n\(\in\){-10,-4,-2,4}