Question

3n-13chia hết cho n+2

Answer 1

\(3n-13⋮\left(n+2\right)\)

\(\Rightarrow3\left(n+2\right)-19⋮\left(n+2\right)\)

\(\Rightarrow19⋮\left(n+2\right)\Rightarrow\left(n+2\right)\inƯ\left(19\right)=\left\{\pm1;\pm19\right\}\)

\(\Rightarrow n\in\left\{-1;-3;17;-21\right\}\)

Answer 2

3n-13 chia hết cho n+2

Mà n+2 chia hết cho n+2

Nên 3(n+2) chia hết cho n+2

     3n+6 chia hết cho n+2

=> (3n-13)-(3n+6) chia hết cho n+2

     => -19 chia hết cho n+2

=> n+2 € Ư(-19)

n+2 € {1;-1;19;-19}

Vậy n € {-1;-3;17;-21}

Answer 3

\(3n-13⋮\left(n+2\right)\)

\(\Rightarrow3\left(n+2\right)-19⋮\left(n+2\right)\)

\(\Rightarrow19⋮\left(n+2\right)\Rightarrow\left(n+2\right)\in\text{Ư}\left(19\right)=\left\{\pm1;\pm19\right\}\)

\(\Rightarrow n\in\left\{-1;-3;17;-21\right\}\)

Answer 4

\(3n-13⋮n+2\)

\(\Rightarrow3\left(n+2\right)-19⋮n-2\)

\(\Rightarrow19⋮n-2\)

\(\Rightarrow n-2\inƯ\left(19\right)=\left\{\pm1;\pm19\right\}\)

Xét bảng

n-2	1	19	-1	-19
n	3	21	1	-17

Vậy............................