\(\dfrac{3\times5}{1\times5}+\dfrac{2}{5}=\dfrac{15}{5}+\dfrac{2}{5}=\dfrac{17}{5}\\ \dfrac{4\times7}{1\times7}-\dfrac{5}{7}=\dfrac{28}{7}-\dfrac{5}{7}=\dfrac{23}{7}\\ 1-\left(\dfrac{2\times3}{5\times3}+\dfrac{1\times5}{3\times5}\right)=1-\left(\dfrac{6}{15}+\dfrac{5}{15}\right)\\ =\dfrac{1\times15}{1\times15}-\dfrac{11}{15}=\dfrac{15}{15}-\dfrac{11}{15}=\dfrac{4}{15}\)
\(\dfrac{17}{5}\)
\(\dfrac{23}{7}\)
\(\dfrac{4}{15}\)