\(\dfrac{38}{11}+\left(\dfrac{16}{13}+\dfrac{6}{11}\right)\\ =\dfrac{38}{11}+\dfrac{16}{13}+\dfrac{6}{11}\\ =\left(\dfrac{38}{11}+\dfrac{6}{11}\right)+\dfrac{16}{13}\\ =\dfrac{44}{11}+\dfrac{16}{13}\\ =4+\dfrac{16}{13}\\ =\dfrac{52}{13}+\dfrac{16}{13}\\ =\dfrac{68}{13}\\ \dfrac{3}{4}:\dfrac{3}{5}-\dfrac{1}{5}\\ =\dfrac{3}{4}\times\dfrac{5}{3}-\dfrac{1}{5}\\ =\dfrac{5}{4}-\dfrac{1}{5}\\ =\dfrac{25-4}{20}\\ =\dfrac{21}{20}\)
Phép tính 1:
\(\dfrac{38}{11}+\left(\dfrac{16}{13}+\dfrac{6}{11}\right)\)
\(=\left(\dfrac{38}{11}+\dfrac{6}{11}\right)+\dfrac{16}{13}\)
\(=4+\dfrac{16}{13}=\dfrac{4\cdot13+16}{13}\)(Dấu "." trong phép tính là dấu nhân)
\(=\dfrac{68}{13}\)
Phép tính 2:
\(\dfrac{3}{4}:\dfrac{3}{5}-\dfrac{1}{5}\)
\(=\dfrac{3}{4}\cdot\dfrac{5}{3}-\dfrac{1}{5}\)
\(=\dfrac{\left(3\cdot5\right):3\cdot5}{\left(4\cdot3\right):3\cdot5}-\dfrac{1\cdot4}{5\cdot4}\)
\(=\dfrac{25}{20}-\dfrac{4}{20}\)
\(=\dfrac{21}{20}\)
