\(\dfrac{3}{8}+\dfrac{3}{24}=\dfrac{3}{8}+\dfrac{1}{8}=\dfrac{3+1}{8}=\dfrac{4}{8}=\dfrac{1}{2}\)
\(\dfrac{3}{8}+\dfrac{3}{24}=\dfrac{9}{24}+\dfrac{3}{24}=\dfrac{12}{24}=\dfrac{1}{2}\)
\(\dfrac{3}{8}=\dfrac{9}{24}\)
\(\dfrac{9}{24}+\dfrac{3}{24}=\dfrac{9+3}{24}=\dfrac{12}{24}=\dfrac{1}{2}\)