Question

(3/7)²¹.(9/49)⁶

 

Answer 1

\(\left(\frac{3}{7}\right)^{21}.\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}.\left(\frac{3^2}{7^2}\right)^6=\left(\frac{3}{7}\right)^{21}.\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^{33}\)

Answer 2

cảm ơn