Question

(3/7)^20 :(9/49)^5

2: (1/2 -2/3)^2

√16 +√0,25 -√0,36

Giải giúp tớ 

Answer 1

chịu thui

+_+    

Answer 2

\(\left(\frac{3}{7}\right)^{20}:\left(\frac{9}{49}\right)^5\)

\(=\left(\frac{3}{7}\right)^{20}:\left(\frac{3^2}{7^2}\right)^5\)

\(=\left(\frac{3}{7}\right)^{20}:\left(\frac{3}{7}\right)^{10}\)

\(=\left(\frac{3}{7}\right)^{10}\)

\(2:\left(\frac{1}{2}-\frac{2}{3}\right)^2\)

\(=2:\left(\frac{3}{6}-\frac{4}{6}\right)^2\)

\(=2:\left(\frac{-1}{6}\right)^2\)

\(=2:\frac{1}{36}=2.36\)

\(=72\)

\(\sqrt{16}+\sqrt{0,25}-\sqrt{0,36}\)

\(=4+0,5-0,6\)

\(=3,9\)

Answer 3

\(\left(\frac{3}{7}\right)^{20}:\left(\frac{9}{49}\right)^5=\frac{3^{20}}{7^{20}}.\frac{7^{10}}{3^{10}}=\left(\frac{3}{7}\right)^{10}\)

\(\frac{2}{\left(\frac{1}{2}-\frac{2}{3}\right)^2}=\frac{2}{\left(\frac{3-4}{2.3}\right)^2}=\frac{2}{\left(\frac{1}{6}\right)^2}=\frac{2.6^2}{1^2}=72\)

\(\sqrt{16}+\sqrt{0,25}-\sqrt{0,36}=4+0,5+0,6=5,1\)

Answer 4

cong sai bai 2

4+0,5-,0,6=3,9