Question

(3/7 + x) : 4/9 = 12/13

Tìm x giúp mình với.

Answer 1

(3/7 + x) : 4/9 = 12/13

3/7 + x = 12/13 . 4/9

3/7 + x = 16/39

x = 16/39 - 3/7

x = -5/273

Answer 2

\(\left(\frac{3}{7}+x\right):\frac{4}{9}=\frac{12}{13}\)

\(\frac{3}{7}+x=\frac{12}{13}\cdot\frac{4}{9}\)

\(\frac{3}{7}+x=\frac{160}{117}\)

\(x=\frac{160}{117}-\frac{3}{7}\)

\(x=\frac{769}{819}\)

Answer 3

\(\frac{3}{7}+x=\frac{12}{13}.\frac{4}{9}\)

\(\frac{3}{7}+x=\frac{16}{39}\)

\(x=\frac{16}{39}-\frac{3}{7}=\frac{-5}{273}\)

Answer 4

\(\left(\frac{3}{7}+x\right):\frac{4}{9}=\frac{12}{13}\)

\(\frac{3}{7}+x=\frac{12}{13}\times\frac{4}{9}\)

\(x=\frac{16}{39}-\frac{3}{7}\)

\(x=\frac{-5}{273}\)

Answer 5

\(\left(\frac{3}{7}+x\right):\frac{4}{9}=\frac{12}{13}\)

       \(\left(\frac{3}{7}+x\right)=\frac{12}{13}\times\frac{4}{9}\)

       \(\left(\frac{3}{7}+x\right)=\frac{16}{39}\)

                         \(x=\frac{3}{7}-\frac{16}{39}\)

                         \(x=\frac{5}{273}\)

Answer 6

( \(\frac{3}{7}\)+ X ) : \(\frac{4}{9}\)= \(\frac{12}{13}\)

( \(\frac{3}{7}\)+ X ) = \(\frac{12}{13}\)x \(\frac{4}{9}\)

( \(\frac{3}{7}\)+ X ) = \(\frac{16}{39}\)

X = \(\frac{16}{39}\)- \(\frac{3}{7}\)

X = \(\frac{-5}{273}\)

Answer 7

3/7 + x = 12/13 X 4/9

3/7 + x = 16/39

x = 16/39 - 3/7

x = -5/273

Answer 8

\(\left(\frac{3}{7}+x\right)\div\frac{4}{9}=\frac{12}{13}\)

\(\Rightarrow\left(\frac{3}{7}+x\right)=\frac{12}{13}\times\frac{4}{9}\)

\(\Rightarrow\left(\frac{3}{7}+x\right)=\frac{16}{39}\)

\(\Rightarrow x=\frac{3}{7}-\frac{16}{39}\)

\(\Rightarrow\frac{5}{273}\)

Code : Breacker