\(\dfrac{3}{7}\cdot\dfrac{7}{3}+0,5\\ =1+0,5\\ =1,5\)
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A= ( -6,17 + \(3\dfrac{5}{9}\) - \(2\dfrac{36}{97}\)) . (\(\dfrac{1}{3}\) - 0,25 - \(\dfrac{1}{12}\))
B= \(\dfrac{0,5-\dfrac{3}{17}}{\dfrac{5}{6}-\dfrac{5}{17}}\) + \(\dfrac{0,5-\dfrac{1}{3}-0,2}{\dfrac{7}{5}+\dfrac{7}{3}-3,5}\)
\(\dfrac{5}{9}\):\(\dfrac{13}{7}\)+\(\dfrac{5}{9}\):\(\dfrac{13}{9}\)-1\(\dfrac{2}{3}\)
4\(\dfrac{2}{5}\):0,5%-1\(\dfrac{3}{7}\).14%+(-0,5)
Tính giúp mik với!!! Mình cảm ơn
2x ( 0,5 + 2/3 ) : 7/3 = 0,25
các bạn tìm x hộ mik nha
a) -2/5x+ 4/3= 7/3
b) (x. 0,5-3/7) : 1/2 =1/7
0,5 x - 2/3 x =7/3
x=4 3/7 y= 0,5 ạ
25% - 3/2 + 0,5 . 12/5
0,25 . 7/3 . 30 . 0,5. 8/45
c) 9/23 . 5/8 + 9/23 . 3/8 - 9/23
0,5.x-2/3.x=7/12
a) -7/25 . 11/13 + -7/25 . 2/13 - 18/25
b) 5/7 . 1/3 - 5/7 . 1/4 - 5/7 . 1/12
c) 5 + 2/5 . 4+ 2/7 + 5 + 5/7 . 5+ 2/5
d) 75% - 3/2 + 0,5 - [ -1/2]^2
a. 3/7 - 9/5 - 4/3
b.0,5 - 3/4 - 2/3