Ta có \(\dfrac{35}{8}=4\dfrac{3}{8}\) và \(\dfrac{47}{11}=4\dfrac{3}{11}\). Vì \(\dfrac{3}{8}>\dfrac{3}{11}\) nên \(4\dfrac{3}{8}>4\dfrac{3}{11}\), suy ra \(\dfrac{35}{8}>\dfrac{47}{11}\)
\(\dfrac{35}{8}=\dfrac{32}{8}+\dfrac{3}{8}=4+\dfrac{3}{8}\\ \dfrac{47}{11}=\dfrac{44}{11}+\dfrac{3}{11}=4+\dfrac{3}{11}\\ Vì:\dfrac{3}{8}>\dfrac{3}{11}\Rightarrow4+\dfrac{3}{8}>4+\dfrac{3}{11}\\ \Rightarrow\dfrac{35}{8}>\dfrac{47}{11}\)