Ta có:
3/5+4/7+2/5+1/7+2/7=(3/5+2/5)+(4/7+1/7+2/7)
= 1 + 1 = 2
3/5+4/7+2/5+1/7+2/7
=(3/5+2/5)+(4/7+2/7+1/7)
=5/5+7/7
=1+1
=2
\(\frac{3}{5}+\frac{4}{7}+\frac{2}{5}+\frac{1}{7}+\frac{2}{7}\)
= \(\left(\frac{3}{5}+\frac{2}{5}\right)\)+ \(\left(\frac{4}{7}+\frac{1}{7}+\frac{2}{7}\right)\)
= \(1+1\)
= \(2\)
Hay \(\frac{2}{1}\)