\(3.5^{2x-6}=75\)
\(5^{2x-6}=75:3\)
\(5^{2x-6}=25\)
\(5^{2x-6}=5^2\)
\(\Rightarrow2x-6=2\)
\(2x=8\)
\(x=4\)
\(3.5^{2x-6}=75\)
\(5^{2x-6}=75\div3\)
\(5^{2x-6}=25\)
\(5^{2x-6}=5^2\)
\(\Rightarrow2x-6=2\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=4\)
3 . 52x - 6 = 75
52x - 6 = 75 : 3
52x - 6 = 25
52x - 6 = 52
=> 2x - 6 = 2
=> 2x = 8
=> x = 4
Vậy x = 4
Ta có: \(3.5^{2x}-6=75\)
\(\Rightarrow3.5^{2x}=75+6=81\)
\(\Rightarrow5^{2x}=81:3=27\)
Mà \(27=3^3\)
=> \(5^{2x}=3^3\) ( không hợp lí)
Vậy \(x\in\theta\)