34x - 1 : 3x = 243
=> 34x - 1 - x = 35
=> 33x - 1 = 35
=> 3x - 1 = 5
=> 3x = 6
=> x = 2
Vậy x = 2
\(3^{4x-1}:3^x=243\)
\(\Rightarrow3^{4x-1}:3^x=3^5\)
\(\Rightarrow4x-1=5\)
\(\Rightarrow4x=5+1\)
\(\Rightarrow4x=6\)
\(\Rightarrow x=\frac{3}{2}\)
Tìm x,y biết:
a) 3 4 x + 1 5 = 1 6 b) 1 3 + 1 2 : x = − 4 c) c ) x − 2 3 x + 1 4 = 0
d) 2 x − 3 3 4 x + 1 = 0 d) 2 3 x + 1 2 − 5 3 = 0 e) 2 x − 0 , 3 = 1 , 5
f) x . − 3 5 3 = − 3 5 5 g) x : 1 3 2 = 1 3 3 h) x 26 = 21 39
k) 1 3 x = 2 3 1 6 l) 77 7 9 5 9 = x 0 , 03 m) 2 2 3 0 , 03 = 1 7 9 x
n) 2 x − 3 2 = 16 o) 3 x − 2 5 = − 243
tìm x
a) 5x(x-3)(x+3)-(2x-3)^2- 5(x+2)^2 +34x(x+2)=1
b) (x-2)^3+ 6(x+1)^2 - (x-3)(x^2+3x+9)=97
3x*3 mu x+1 =243
Tìm x, biết rằng: a) 2x = 16 b) 3x+1 = 9xc) 23x+2 = 4x+5d) 32x-1 = 243
1,3^2x-1=243
3^x+1=9
2^3x+2=4^x+5
3x . (1 phần 3 ) 3 . 9 = 243
27<813:3x<243
a, (2x-3)2=16
b, (3x-2)5=-243
c, (x-7)x+1=(x-7)x+11
Tìm x, biết:
a) \(\left(-\dfrac{1}{3}\right)^3\) .x = \(\dfrac{1}{81}\)
b) 22 . 16 >2x > 42
c) 9.27 < 3x < 243
Tìm x,biết: a)(x-2,5)^4=(x-2,5)^2
b)(3x-1)^10=(3x-1)^20
c)x^8/243=27
d)32^x.16^x=1024
