\(3^4.3^x:9=3^7\)
\(\Leftrightarrow3^{4+x}:3^2=3^7\)
\(\Leftrightarrow3^{4+x-2}=3^7\)
\(\Rightarrow2+x=7\)
\(\Leftrightarrow x=5\)
Ta có : 34 . 3x : 9 = 37
34 . 3x : 32 = 37
34 . 3x = 37 . 32
34 .3x = 39
3x = 39 : 34
3 x = 35
=> x = 5
Vậy x= 5
\(3^4.3^x:9=3^7\)
\(3^4\times3^x:3^2=3^7\)
\(\Rightarrow3^4.3^x=3^7:3^2\)
\(\Rightarrow3^4.3^x=3^5\)
\(\Rightarrow3^{4+x}=3^5\)
\(\Rightarrow4+x=5\)
\(\Rightarrow x=5-4\)
\(\Rightarrow x=1\)
\(3^4.3^x:9=3^7\)
\(3^4.3^x:3^3=3^7\)
\(3^4.3^x=3^7.3^3\)
\(3^4.3^x=3^{10}\)
\(3^x=3^{10}:3^4\)
\(3^x=3^6\)
\(x=6\)