3.(4-x) - 2.(x-1) = x + 20
<=> 12 - 3x - 2x + 2 = x + 20
<=> -6x = 6
<=> x = -1
4.(2x+7) - 3( 3x - 2 ) = 24
<=> 8x + 28 - 9x + 6 = 24
<=> -x = -10
<=> x = 10
3(x-2) + 2x = 10
<=> 3x - 6 + 2x = 10
<=> 5x = 16
<=> x = \(\frac{16}{5}\)
a, 3( 4-x) - 2(x-1) = x + 20
12 - 3x - 2x -2 = x + 20
10 - x = x + 20
=> 2x = 10 -(+20)
2x = 10 - 20
2x = -10
=> x = -10 : 2
=> x = -5
Vậy x = -5
b, 4(2x + 7) - 3(3x - 2) = 24
8x + 28 - 9x -9 = 24
=> -x + 19 = 24
-x = 24 - 19
=> -x = 5
=> x = -5
Vậy x = -5
c, 3(x - 2) + 2x = 10
3x - 6 + 2x = 10
5x - 6 = 10
5x = 10 + 6
5x = 16
=> x = \(\frac{16}{5}\)
Vậy x = \(\frac{16}{5}\)
3.(4-x)-2.(x-1)=x+20
<=> 12-3x-2x+2=x+20
<=> -3x-2x-x=20-12-2
<=> -6x = 6
<=> x=-1
a, ta có 3.(4-x)-2.(x-1)=x+20
<-> 12-3x-2x+2= x+20( nhân há ngoặc)
<-> -3x-2x-x=20-12-2( chuyển vế x sang 1 bên ố sang 1 bên đổi dấu)
<-> -6x=6
-> x=-1
b, ta có 4.(2x +7)-3.(3x-2)=24
<-> 8x+28-9x+6=24
<-> 8x-9x=24-28-6
<--> -x= -10
-> x= 10
c, ta có 3.( x-2) +2x=10
<-> 3x-6+2x=10
3x+2x=10+6
<-> 5x= 16
-> x=16/5