\(\dfrac{3}{4}-\dfrac{6}{21}=\dfrac{63}{84}-\dfrac{24}{84}=\dfrac{39}{84}=\dfrac{13}{28}\)
\(\dfrac{3}{4}-\dfrac{6}{21}=\dfrac{3\times21}{4\times21}-\dfrac{6\times4}{21\times4}=\dfrac{63}{84}-\dfrac{24}{84}=\dfrac{13}{28}\)
\(\dfrac{3}{4}-\dfrac{6}{21}=\dfrac{3}{4}-\dfrac{2}{7}=\dfrac{21}{28}-\dfrac{8}{28}=\dfrac{13}{28}\)