Question

3/3.5+3/5.7+3/7.9+...+3/49.51 = ?

Answer 1

\(\frac{3}{3.5}+\frac{3}{5.7}+\frac{3}{7.9}+....+\frac{3}{49.51}\)

= 3. \(\frac{1}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+....+\frac{1}{49}-\frac{1}{51}\right)\)

=\(\frac{3}{2}\left(\frac{1}{3}-\frac{1}{51}\right)\)

=\(\frac{3}{2}.\frac{16}{51}\)

=\(\frac{8}{17}\)

Answer 2

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